设函数f(x)=sin(wx+q)+cos(wx+q)(w>0,q的绝对值

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设函数f(x)=sin(wx+q)+cos(wx+q)(w>0,q的绝对值
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设函数f(x)=sin(wx+q)+cos(wx+q)(w>0,q的绝对值
设函数f(x)=sin(wx+q)+cos(wx+q)(w>0,q的绝对值

设函数f(x)=sin(wx+q)+cos(wx+q)(w>0,q的绝对值
易得f(x)=sin(wx+q)+cos(wx+q)=√2sin(wx+q+π/4),最小正周期为pai得w=2,f(-x)=f(x)得q=π/4,所以=√2sin(2(x+π/4)),求导后f(x)在(0,π/2)单调递减..会了吧.