2道初中证明题,如下!图自己画下吧,1、已知三角形ABC中,∠C=90°,在BC上任取一点D,连接AD,以BA为边向外作∠BAE=∠CAD,∠ABE=90°,且边AE和BE相交于E相交于E,再从E作EF垂直于CB边的延长线于F.求证:CD=BF
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![2道初中证明题,如下!图自己画下吧,1、已知三角形ABC中,∠C=90°,在BC上任取一点D,连接AD,以BA为边向外作∠BAE=∠CAD,∠ABE=90°,且边AE和BE相交于E相交于E,再从E作EF垂直于CB边的延长线于F.求证:CD=BF](/uploads/image/z/8441665-25-5.jpg?t=2%E9%81%93%E5%88%9D%E4%B8%AD%E8%AF%81%E6%98%8E%E9%A2%98%2C%E5%A6%82%E4%B8%8B%21%E5%9B%BE%E8%87%AA%E5%B7%B1%E7%94%BB%E4%B8%8B%E5%90%A7%2C1%E3%80%81%E5%B7%B2%E7%9F%A5%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E2%88%A0C%3D90%C2%B0%2C%E5%9C%A8BC%E4%B8%8A%E4%BB%BB%E5%8F%96%E4%B8%80%E7%82%B9D%2C%E8%BF%9E%E6%8E%A5AD%2C%E4%BB%A5BA%E4%B8%BA%E8%BE%B9%E5%90%91%E5%A4%96%E4%BD%9C%E2%88%A0BAE%3D%E2%88%A0CAD%2C%E2%88%A0ABE%3D90%C2%B0%2C%E4%B8%94%E8%BE%B9AE%E5%92%8CBE%E7%9B%B8%E4%BA%A4%E4%BA%8EE%E7%9B%B8%E4%BA%A4%E4%BA%8EE%2C%E5%86%8D%E4%BB%8EE%E4%BD%9CEF%E5%9E%82%E7%9B%B4%E4%BA%8ECB%E8%BE%B9%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8EF.%E6%B1%82%E8%AF%81%EF%BC%9ACD%3DBF)
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