(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊

(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z 已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX.. x:y:z=3:4:5 2x-3y+2z=8 x-y-2z=? (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian x+y+z=-1 4x-2y+3z=5 y-z=8-2x x+y+z=51 4x+8y+5z=300 x+y+2z=67 已知关于x y z的方程组2x-3y+5z=7 x+2y-3z=8,则4x+y-z= 解三元一次方程组1、x+y-z=4 2x-y+z=5 x-3y+z=-2 2、y+2z=-2 3x+y-4z=1 2x-y+2z=8 3、x-2y+z=-1 x+y+z=2x+2y+3z=-1 三元一次方程组2x+z=3 3x+y-z=8 x+3y+2z=3 5x+2y-3z=2 x+2y+z=6 7x-2y-4z=262x+z=3 3x+y-z=8 x+3y+2z=3 5x+2y-3z=2 x+2y+z=6 7x-2y-4z=26 6x-y-z=3 2x-4y+8z=5 3x-6y-z=10 y z 分别等于几?大虾 {x+y+z=1;x+3y+7z=-1;z+5y+8z=-2 (x-y)^2+4z(x-y)+4z^2 设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z) 计算:(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z) 2(x+y-z)-3(x-y+z)-5(x+y-z)+6(x-y+z) 计算