已知正方体ABCD-A1B1C1D1中,E、F分别为D1C1,C1B1的中点,AC∩BD=P,A1C1∩EF=Q,求证:(1)D,B,E,F四点共面 (2)若A1C交平面DBFE于R点,则P,Q,R三点共线
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![已知正方体ABCD-A1B1C1D1中,E、F分别为D1C1,C1B1的中点,AC∩BD=P,A1C1∩EF=Q,求证:(1)D,B,E,F四点共面 (2)若A1C交平面DBFE于R点,则P,Q,R三点共线](/uploads/image/z/7226735-23-5.jpg?t=%E5%B7%B2%E7%9F%A5%E6%AD%A3%E6%96%B9%E4%BD%93ABCD-A1B1C1D1%E4%B8%AD%2CE%E3%80%81F%E5%88%86%E5%88%AB%E4%B8%BAD1C1%2CC1B1%E7%9A%84%E4%B8%AD%E7%82%B9%2CAC%E2%88%A9BD%3DP%2CA1C1%E2%88%A9EF%3DQ%2C%E6%B1%82%E8%AF%81%EF%BC%9A%EF%BC%881%EF%BC%89D%2CB%2CE%2CF%E5%9B%9B%E7%82%B9%E5%85%B1%E9%9D%A2+%EF%BC%882%EF%BC%89%E8%8B%A5A1C%E4%BA%A4%E5%B9%B3%E9%9D%A2DBFE%E4%BA%8ER%E7%82%B9%2C%E5%88%99P%2CQ%2CR%E4%B8%89%E7%82%B9%E5%85%B1%E7%BA%BF)
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