问几道有关分式的数学题 ,(1)[(5xy)/(x²+xy)]*[(xy+y²)/(2x²y²)]^3(2)[(x^3-3x+4)/(x²+2x-3)]÷[(x²-16)/(x²+6x+9)](3)(x²+x-3)/(x²+x-2)+1=(2x²+4x+1)/(x²+2x+1)(4)已知a²+4a+1=0 ,且(a^4+
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![问几道有关分式的数学题 ,(1)[(5xy)/(x²+xy)]*[(xy+y²)/(2x²y²)]^3(2)[(x^3-3x+4)/(x²+2x-3)]÷[(x²-16)/(x²+6x+9)](3)(x²+x-3)/(x²+x-2)+1=(2x²+4x+1)/(x²+2x+1)(4)已知a²+4a+1=0 ,且(a^4+](/uploads/image/z/7002583-7-3.jpg?t=%E9%97%AE%E5%87%A0%E9%81%93%E6%9C%89%E5%85%B3%E5%88%86%E5%BC%8F%E7%9A%84%E6%95%B0%E5%AD%A6%E9%A2%98+%2C%281%29%5B%285xy%29%2F%28x%26sup2%3B%2Bxy%29%5D%2A%5B%28xy%2By%26sup2%3B%29%2F%282x%26sup2%3By%26sup2%3B%29%5D%5E3%282%29%5B%28x%5E3-3x%2B4%29%2F%28x%26sup2%3B%2B2x-3%29%5D%C3%B7%5B%28x%26sup2%3B-16%29%2F%28x%26sup2%3B%2B6x%2B9%29%5D%283%29%28x%26sup2%3B%2Bx-3%29%2F%28x%26sup2%3B%2Bx-2%29%2B1%3D%282x%26sup2%3B%2B4x%2B1%29%2F%28x%26sup2%3B%2B2x%2B1%29%284%29%E5%B7%B2%E7%9F%A5a%26sup2%3B%2B4a%2B1%3D0+%2C%E4%B8%94%28a%5E4%2B)
问几道有关分式的数学题 ,(1)[(5xy)/(x²+xy)]*[(xy+y²)/(2x²y²)]^3(2)[(x^3-3x+4)/(x²+2x-3)]÷[(x²-16)/(x²+6x+9)](3)(x²+x-3)/(x²+x-2)+1=(2x²+4x+1)/(x²+2x+1)(4)已知a²+4a+1=0 ,且(a^4+
问几道有关分式的数学题 ,
(1)
[(5xy)/(x²+xy)]*[(xy+y²)/(2x²y²)]^3
(2)
[(x^3-3x+4)/(x²+2x-3)]÷[(x²-16)/(x²+6x+9)]
(3)
(x²+x-3)/(x²+x-2)+1=(2x²+4x+1)/(x²+2x+1)
(4)
已知a²+4a+1=0 ,且(a^4+ma²+1)/(2a^3+ma²+2a)=3 ,试确定m 的值.
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额,写得好的我会加分的说,
问几道有关分式的数学题 ,(1)[(5xy)/(x²+xy)]*[(xy+y²)/(2x²y²)]^3(2)[(x^3-3x+4)/(x²+2x-3)]÷[(x²-16)/(x²+6x+9)](3)(x²+x-3)/(x²+x-2)+1=(2x²+4x+1)/(x²+2x+1)(4)已知a²+4a+1=0 ,且(a^4+
1 (5xy)/(x²+xy)=5y/(x+y)
(xy+y²)/(2x²y²)^3=(x+y)/(2x²y)^3
[5y/(x+y)]*[(x+y)/(2x²y)]^3=[5/(x+y)]*[(x+y)^3/(2x^6y²)]=5*(x+y)^2/(8x^6y²)
2 x^3-3x+4不能分解 可能操错啦 好好看看
x²+2x-3=(x+3)(x-1)
x²-16=(x-4)(x+4)
x²+6x+9=(x+3)(x+3)
3 x²+x-3=(x+2)(x-1)
x²+x-2=(x+2)(x-1)
x²+2x+1=(x+1)(x+1)
整理可得2x+1=0 x=
4