解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12)过程请明示,谢

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/29 08:02:25
解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12)过程请明示,谢
x){|i;~JBXSRHVB64 `a#@m/o6]:/6,I*ҧDv,©z~nӉ q@c+ul+@ͭ561Э5*6`@ #c K {) [SJ[3<;7 ّ&

解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12)过程请明示,谢
解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12)
过程请明示,谢

解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12)过程请明示,谢
.死算呗
xy-2x+3y-6=xy+10x-3y-30,2x-y=4
xy+3x+y+3=xy+12x-2y-24,3x-y=9
2式减1式,x=5,y=6