求50道初二二次根式计算题

来源:学生作业帮助网 编辑:作业帮 时间:2024/06/21 01:20:48
求50道初二二次根式计算题
xV[kdE+!0NR}$>X\Ψw"Nd_ia >DaA|%o'dL@f@LU}]ud%}W/|ן_g<{ϋӿ_zD‘wot=#[Gao{tx8yh<LwǏwhdtQoJt|+\,D- ϸrJ=ai 2, 95X=0'H%mEE͹˒3*`6Xʵ6J@2 \i7d0G=3dQ\pYL16' NJ$-A[hF1YeD<,p1\48~&/|c#!na{rhDy σ ec| qq|jJb˃X]#{T@1u½BTAT!5ʡ.cW5ub{RnQvM`V.`0U]K٠́YQݤzV*\a&0x<{<(GQ?<3j"V(叺|?Ve*om0пǛШncɺ?U%xnXmvy]aX*ڸ+s{G4*a튥R4Pt.s mh+们hwf\. =>+je6XcUY_0n]ϕ%ś+)8=- ڵ˅YZY@Գ=jL(W!0c++DĢ{=\u6< lV.J!I{15h;EuEF9"@K { '\VO|ГxHq+1M}KM,cx5{QhexYynRxjT*SnV.+2J JKLuHۄ5k,'q,*q<%WW9JTL12Vr 5F]65(:nې Ep| K

求50道初二二次根式计算题
求50道初二二次根式计算题

求50道初二二次根式计算题


①5√8-2√32+√50
=5*3√2-2*4√2+5√2
=√2(15-8+5)
=12√2
②√6-√3/2-√2/3
=√6-√6/2-√6/3
=√6/6
③(√45+√27)-(√4/3+√125)
=(3√5+3√3)-(2√3/3+5√5)
=-2√5+7√5/3
④(√4a-√50b)-2(√b/2+√9a)
=(2√a-5√2b)-2(√2b/2+3√a)
=-4√a-6√2b
⑤√4x*(√3x/2-√x/6)
=2√x(√6x/2-√6x/6)
=2√x*(√6x/3)
=2/3*|x|*√6
⑥(x√y-y√x)÷√xy
=x√y÷√xy-y√x÷√xy
=√x-√y
⑦(3√7+2√3)(2√3-3√7)
=(2√3)^2-(3√7)^2
=12-63
=-51
⑧(√32-3√3)(4√2+√27)
=(4√2-3√3)(4√2+3√3)
=(4√2)^2-(3√3)^2
=32-27
=5
⑨(3√6-√4)?
=(3√6)^2-2*3√6*√4+(√4)^2
=54-12√6+4
=58-12√6
⑩(1+√2-√3)(1-√2+√3)
=[1+(√2-√3)][1-(√2-√3)]
=1-(√2-√3)^2
=1-(2+3+2√6)
=-4-2√6

(1)5√12×√18
=5*2√3*3√2
=30√6;

(2)-6√45×(-4√48)
=6*3√5*4*4√3
=288√15;

(3)√(12a)×√(3a) /4
=√(36a^2)/4
=6a/4
=3a/2.