x+y/2=2y-z/3=2 x-3y+z=10

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x+y/2=2y-z/3=2 x-3y+z=10
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x+y/2=2y-z/3=2 x-3y+z=10
x+y/2=2y-z/3=2 x-3y+z=10

x+y/2=2y-z/3=2 x-3y+z=10
x+y/2=2y-z/3=2
*6后=3x+3y=4y-2z=12
得x+y=4①
2y-z=6②
①-②=x-y+z=-2③
x-3y+z=10 ④
④-③=-2y=12
y=-6
代入x+y/2=2得x=10
代入2y-z/3=2得z=-18

x+y/2=2y-z/3=2
即x+y=4,2y-z=6
两式相减,x-y+z=-2

x-3y+z=10 ,x-y+z=-2
两式相减,-2y=12,则y=-6

将y=-6代入x+y=4,2y-z=6,
解得x=10,z=-18

所以,方程的解为x=10,y=-6,z=-18