以前会写,现在忘了.△ABC是个等腰三角形,AB=AC,∠BAC=120°,AB的垂直平分线交AB于D点,连接CD,求∠CDA的度数对不起,我重新讲下题目,△ABC是个等腰三角形,AB=AC,点D是腰AB上的中点,连接DC,∠A=
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/20 22:24:18
![以前会写,现在忘了.△ABC是个等腰三角形,AB=AC,∠BAC=120°,AB的垂直平分线交AB于D点,连接CD,求∠CDA的度数对不起,我重新讲下题目,△ABC是个等腰三角形,AB=AC,点D是腰AB上的中点,连接DC,∠A=](/uploads/image/z/15039346-58-6.jpg?t=%E4%BB%A5%E5%89%8D%E4%BC%9A%E5%86%99%2C%E7%8E%B0%E5%9C%A8%E5%BF%98%E4%BA%86.%E2%96%B3ABC%E6%98%AF%E4%B8%AA%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2%2CAB%3DAC%2C%E2%88%A0BAC%3D120%C2%B0%2CAB%E7%9A%84%E5%9E%82%E7%9B%B4%E5%B9%B3%E5%88%86%E7%BA%BF%E4%BA%A4AB%E4%BA%8ED%E7%82%B9%2C%E8%BF%9E%E6%8E%A5CD%2C%E6%B1%82%E2%88%A0CDA%E7%9A%84%E5%BA%A6%E6%95%B0%E5%AF%B9%E4%B8%8D%E8%B5%B7%EF%BC%8C%E6%88%91%E9%87%8D%E6%96%B0%E8%AE%B2%E4%B8%8B%E9%A2%98%E7%9B%AE%EF%BC%8C%E2%96%B3ABC%E6%98%AF%E4%B8%AA%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2%EF%BC%8CAB%3DAC%EF%BC%8C%E7%82%B9D%E6%98%AF%E8%85%B0AB%E4%B8%8A%E7%9A%84%E4%B8%AD%E7%82%B9%EF%BC%8C%E8%BF%9E%E6%8E%A5DC%EF%BC%8C%E2%88%A0A%3D)
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