求二次根式的性质的问题1.化去被开放式的分母:√(9/2)2.使等式√(a/a+3)=(√a)/(√a+3)成立的条件是( )3.当a>3,化简√[(a-2)^2(3-a)^2]的结果( )4.把-1/m√(-m^3)中根号外的因式适当变形后移至根
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/21 01:35:35
![求二次根式的性质的问题1.化去被开放式的分母:√(9/2)2.使等式√(a/a+3)=(√a)/(√a+3)成立的条件是( )3.当a>3,化简√[(a-2)^2(3-a)^2]的结果( )4.把-1/m√(-m^3)中根号外的因式适当变形后移至根](/uploads/image/z/1379787-51-7.jpg?t=%E6%B1%82%E4%BA%8C%E6%AC%A1%E6%A0%B9%E5%BC%8F%E7%9A%84%E6%80%A7%E8%B4%A8%E7%9A%84%E9%97%AE%E9%A2%981.%E5%8C%96%E5%8E%BB%E8%A2%AB%E5%BC%80%E6%94%BE%E5%BC%8F%E7%9A%84%E5%88%86%E6%AF%8D%EF%BC%9A%E2%88%9A%289%2F2%292.%E4%BD%BF%E7%AD%89%E5%BC%8F%E2%88%9A%28a%2Fa%2B3%29%3D%28%E2%88%9Aa%29%2F%28%E2%88%9Aa%2B3%29%E6%88%90%E7%AB%8B%E7%9A%84%E6%9D%A1%E4%BB%B6%E6%98%AF%EF%BC%88+%EF%BC%893.%E5%BD%93a%3E3%2C%E5%8C%96%E7%AE%80%E2%88%9A%5B%EF%BC%88a-2%29%5E2%283-a%29%5E2%5D%E7%9A%84%E7%BB%93%E6%9E%9C%EF%BC%88+%EF%BC%894.%E6%8A%8A-1%2Fm%E2%88%9A%28-m%5E3%29%E4%B8%AD%E6%A0%B9%E5%8F%B7%E5%A4%96%E7%9A%84%E5%9B%A0%E5%BC%8F%E9%80%82%E5%BD%93%E5%8F%98%E5%BD%A2%E5%90%8E%E7%A7%BB%E8%87%B3%E6%A0%B9)
xRN@;II=T⣕GMPD1FY'3-wZK&jtj={\%gg
vإVWN2ܹ6+HeZfzQT_c߮jlaNO Y(8 fqZñYҷ16dJD ^h I`!cr1eUbo5S"HH(,8܆@˼ǽCfek͢۶[){3D@i I1|1PCZ)