已知m-n=2,mn=1,求多项式(-2mn+2mn+3n)-(3mn+2n-2m)-(m+4n+mn)的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/06/10 23:02:39
已知m-n=2,mn=1,求多项式(-2mn+2mn+3n)-(3mn+2n-2m)-(m+4n+mn)的值
x){}Ksultrl umlzd˅;5aaMR>/^NdWγ);hx,3 `ee@EF nInnT(| aFiAX6yvP?ڀ9//z3"ݤHmpNDnTF(bnr/>

已知m-n=2,mn=1,求多项式(-2mn+2mn+3n)-(3mn+2n-2m)-(m+4n+mn)的值
已知m-n=2,mn=1,求多项式(-2mn+2mn+3n)-(3mn+2n-2m)-(m+4n+mn)的值

已知m-n=2,mn=1,求多项式(-2mn+2mn+3n)-(3mn+2n-2m)-(m+4n+mn)的值
错了,改一下
(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)
=-2mn+2m+3n-3mn-2n+2m-m-4n-mn
=-6mn+3m-3n
=-6mn+3(m-n)
=-6+6
=0

解:化简(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)
=-2mn+2mn+3n-3mn-2n+2m-m-4n-mn
=-6mn+3m-3n
=-6×1+3(m-n)
=-6+3×2
=0