f(x)=tan^2x+2tanx+2,求f(x)的最大值和最小值-π/3
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f(x)=tan^2x+2tanx+2,求f(x)的最大值和最小值-π/3
f(x)=tan^2x+2tanx+2,求f(x)的最大值和最小值
-π/3
f(x)=tan^2x+2tanx+2,求f(x)的最大值和最小值-π/3
当-π/3
f(x)=(tanx+1)^2+1;
-π/3<=x<=π/4,-根号3<=tanx<=1;
当tanx=1,f(x)有最大值是:5 ;
当tanx=-1,f(x)有最小值是:1;