f(x)=(1-sinx)/(2-cosx)求值域

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f(x)=(1-sinx)/(2-cosx)求值域
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f(x)=(1-sinx)/(2-cosx)求值域
f(x)=(1-sinx)/(2-cosx)求值域

f(x)=(1-sinx)/(2-cosx)求值域
f(x)= (1-sinx)/(2-cosx)
f'(x) = [-(2-cosx)cosx+ (1-sinx)sinx ]/(2-cosx)^2 =0
-(2-cosx)cosx+ (1-sinx)sinx=0
(cosx)^2-(sinx)^2 = 1
cos2x=1
2x = 0, 2π,..
x =0 (max) or π (min)
f(0) = 1
f(π) = 0
值域 =[0,1]