f(x)=【(x+1)²+sinx】/(x²+1),导函数为f'(x),则f(2012)+f'(2012)+f(-2012)+f'(-2012)=?
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![f(x)=【(x+1)²+sinx】/(x²+1),导函数为f'(x),则f(2012)+f'(2012)+f(-2012)+f'(-2012)=?](/uploads/image/z/7020857-65-7.jpg?t=f%28x%29%3D%E3%80%90%28x%2B1%29%26%23178%3B%2Bsinx%E3%80%91%2F%EF%BC%88x%26%23178%3B%2B1%EF%BC%89%2C%E5%AF%BC%E5%87%BD%E6%95%B0%E4%B8%BAf%27%28x%29%2C%E5%88%99f%282012%29%2Bf%27%282012%29%2Bf%28-2012%29%2Bf%27%28-2012%29%3D%3F)
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f(x)=【(x+1)²+sinx】/(x²+1),导函数为f'(x),则f(2012)+f'(2012)+f(-2012)+f'(-2012)=?
f(x)=【(x+1)²+sinx】/(x²+1),导函数为f'(x),则f(2012)+f'(2012)+f(-2012)+f'(-2012)=?
f(x)=【(x+1)²+sinx】/(x²+1),导函数为f'(x),则f(2012)+f'(2012)+f(-2012)+f'(-2012)=?
你确定题目是对的,我怎么感觉是f(2012)+f'(2012)+f(-2012)-f'(-2012)=?