若m=根号2+1,n=1-根号2,求m²-mn+n²的值
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若m=根号2+1,n=1-根号2,求m²-mn+n²的值
若m=根号2+1,n=1-根号2,求m²-mn+n²的值
若m=根号2+1,n=1-根号2,求m²-mn+n²的值
m=√2+1,n=1-√2
m+n=2
m-n=2√2
mn=-1
m²-mn+n²
=m(m+n)-2mn+n²
=2m-2mn+n²
==2m+2+n(m+n)-mn
=2m+2+2n+1
=2(m+n)+3
=7
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