圆x^2+y^2+2kx+k^2-1=0与圆x^2+y^2+2(k+1)y+k^2+2k=0的圆心之间最短距离是
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圆x^2+y^2+2kx+k^2-1=0与圆x^2+y^2+2(k+1)y+k^2+2k=0的圆心之间最短距离是
圆x^2+y^2+2kx+k^2-1=0与圆x^2+y^2+2(k+1)y+k^2+2k=0的圆心之间最短距离是
圆x^2+y^2+2kx+k^2-1=0与圆x^2+y^2+2(k+1)y+k^2+2k=0的圆心之间最短距离是
x²+y²+2kx+k²-1=0
(x+k)²+y²=1
圆心(-k,0)
x²+y²+2(k+1)y+k²+2k=0
x²+(y+k+1)²=1
圆心(0.-k-1)
d=√(-k-0)²+(0+k+1)²=√(2k²+2k+1)
令t=2k²+2k+1,t=2(k²+k)+1=2(k+1/2)²+1/2
当k=-1/2时,t=1/2
d=√2/2