已知抛物线y=ax^2经过点a(-2,-8).(1)求a的值.(2)判断点B(-1,-4)是否已知抛物线y=ax^2经过点a(-2,-8).(1)求a的值.(2)判断点B(-1,-4)是否在此抛物线上.(3)求出此抛物线上纵坐标为-6的点的坐标
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![已知抛物线y=ax^2经过点a(-2,-8).(1)求a的值.(2)判断点B(-1,-4)是否已知抛物线y=ax^2经过点a(-2,-8).(1)求a的值.(2)判断点B(-1,-4)是否在此抛物线上.(3)求出此抛物线上纵坐标为-6的点的坐标](/uploads/image/z/3817111-31-1.jpg?t=%E5%B7%B2%E7%9F%A5%E6%8A%9B%E7%89%A9%E7%BA%BFy%3Dax%5E2%E7%BB%8F%E8%BF%87%E7%82%B9a%28-2%2C-8%29.%EF%BC%881%EF%BC%89%E6%B1%82a%E7%9A%84%E5%80%BC.%EF%BC%882%EF%BC%89%E5%88%A4%E6%96%AD%E7%82%B9B%28-1%2C-4%29%E6%98%AF%E5%90%A6%E5%B7%B2%E7%9F%A5%E6%8A%9B%E7%89%A9%E7%BA%BFy%3Dax%5E2%E7%BB%8F%E8%BF%87%E7%82%B9a%28-2%2C-8%29.%EF%BC%881%EF%BC%89%E6%B1%82a%E7%9A%84%E5%80%BC.%EF%BC%882%EF%BC%89%E5%88%A4%E6%96%AD%E7%82%B9B%28-1%2C-4%29%E6%98%AF%E5%90%A6%E5%9C%A8%E6%AD%A4%E6%8A%9B%E7%89%A9%E7%BA%BF%E4%B8%8A.%EF%BC%883%EF%BC%89%E6%B1%82%E5%87%BA%E6%AD%A4%E6%8A%9B%E7%89%A9%E7%BA%BF%E4%B8%8A%E7%BA%B5%E5%9D%90%E6%A0%87%E4%B8%BA-6%E7%9A%84%E7%82%B9%E7%9A%84%E5%9D%90%E6%A0%87)
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已知抛物线y=ax^2经过点a(-2,-8).(1)求a的值.(2)判断点B(-1,-4)是否已知抛物线y=ax^2经过点a(-2,-8).(1)求a的值.(2)判断点B(-1,-4)是否在此抛物线上.(3)求出此抛物线上纵坐标为-6的点的坐标
已知抛物线y=ax^2经过点a(-2,-8).(1)求a的值.(2)判断点B(-1,-4)是否
已知抛物线y=ax^2经过点a(-2,-8).
(1)求a的值.
(2)判断点B(-1,-4)是否在此抛物线上.
(3)求出此抛物线上纵坐标为-6的点的坐标.
已知抛物线y=ax^2经过点a(-2,-8).(1)求a的值.(2)判断点B(-1,-4)是否已知抛物线y=ax^2经过点a(-2,-8).(1)求a的值.(2)判断点B(-1,-4)是否在此抛物线上.(3)求出此抛物线上纵坐标为-6的点的坐标
答:
1)
抛物线y=ax^2经过点a(-2,-8)
代入得:a*(-2)^2=-8,4a=-8
解得:a=-2
2)
y=-2x^2
点B(-1,-4)的x=-1代入得:y=-2*(-1)^2=-2
所以:点B不在此抛物线上
(3)
y=-2x^2=-6
x^2=3
x=√3或者x=-√3
所以:所求点为(√3,-6)或者(√3,6)