若方程x²-2(k-3)+k²-4k-1=0 求满足条件m最小值若方程x²-2(k-3)+k²-4k-1=0 的两根之积为m,求满足条件m最小值
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![若方程x²-2(k-3)+k²-4k-1=0 求满足条件m最小值若方程x²-2(k-3)+k²-4k-1=0 的两根之积为m,求满足条件m最小值](/uploads/image/z/3776568-24-8.jpg?t=%E8%8B%A5%E6%96%B9%E7%A8%8Bx%26%23178%3B-2%EF%BC%88k-3%EF%BC%89%2Bk%26%23178%3B-4k-1%3D0+%E6%B1%82%E6%BB%A1%E8%B6%B3%E6%9D%A1%E4%BB%B6m%E6%9C%80%E5%B0%8F%E5%80%BC%E8%8B%A5%E6%96%B9%E7%A8%8Bx%26%23178%3B-2%EF%BC%88k-3%EF%BC%89%2Bk%26%23178%3B-4k-1%3D0+%E7%9A%84%E4%B8%A4%E6%A0%B9%E4%B9%8B%E7%A7%AF%E4%B8%BAm%EF%BC%8C%E6%B1%82%E6%BB%A1%E8%B6%B3%E6%9D%A1%E4%BB%B6m%E6%9C%80%E5%B0%8F%E5%80%BC)
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若方程x²-2(k-3)+k²-4k-1=0 求满足条件m最小值若方程x²-2(k-3)+k²-4k-1=0 的两根之积为m,求满足条件m最小值
若方程x²-2(k-3)+k²-4k-1=0 求满足条件m最小值
若方程x²-2(k-3)+k²-4k-1=0 的两根之积为m,求满足条件m最小值
若方程x²-2(k-3)+k²-4k-1=0 求满足条件m最小值若方程x²-2(k-3)+k²-4k-1=0 的两根之积为m,求满足条件m最小值
答
先需要判断
Δ=4(k-3)²-4(k²-4k-1)>=0
k
两根之积m=k²-4k-1=k²-4k+4-5=(k-2)^2-5≥-5
最小值-5