求1!+2!+3!+...+7!,表示7的阶乘,C语言编程填好一下程序#include long jc( long x){ long k,fac=1;for(k=1;________;k++)fac *=k ;________;}void main( ){ long n,sum=0;long jc(long x);for(n=1;n
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/17 05:32:31
![求1!+2!+3!+...+7!,表示7的阶乘,C语言编程填好一下程序#include long jc( long x){ long k,fac=1;for(k=1;________;k++)fac *=k ;________;}void main( ){ long n,sum=0;long jc(long x);for(n=1;n](/uploads/image/z/310707-27-7.jpg?t=%E6%B1%821%21%2B2%21%2B3%21%2B...%2B7%21%2C%E8%A1%A8%E7%A4%BA7%E7%9A%84%E9%98%B6%E4%B9%98%2CC%E8%AF%AD%E8%A8%80%E7%BC%96%E7%A8%8B%E5%A1%AB%E5%A5%BD%E4%B8%80%E4%B8%8B%E7%A8%8B%E5%BA%8F%23include+long+jc%28+long+x%29%7B+long+k%2Cfac%3D1%3Bfor%28k%3D1%3B________%3Bk%2B%2B%29fac+%2A%3Dk+%3B________%3B%7Dvoid+main%28+%29%7B+long+n%2Csum%3D0%3Blong+jc%28long+x%29%3Bfor%28n%3D1%3Bn)
求1!+2!+3!+...+7!,表示7的阶乘,C语言编程填好一下程序#include long jc( long x){ long k,fac=1;for(k=1;________;k++)fac *=k ;________;}void main( ){ long n,sum=0;long jc(long x);for(n=1;n
求1!+2!+3!+...+7!,表示7的阶乘,C语言编程
填好一下程序#include
long jc( long x)
{
long k,fac=1;
for(k=1;________;k++)
fac *=k ;
________;
}
void main( )
{
long n,sum=0;
long jc(long x);
for(n=1;n
求1!+2!+3!+...+7!,表示7的阶乘,C语言编程填好一下程序#include long jc( long x){ long k,fac=1;for(k=1;________;k++)fac *=k ;________;}void main( ){ long n,sum=0;long jc(long x);for(n=1;n
#include"stdio.h"
#include"math.h"
main()
{
float b[20]=,m,p=0,c;//0的阶乘是1..
int i,j,k,a[100],stop,n;
scanf("%d",&n);//最好用%d
//{这个大括号加得很奇怪.
//不建议下面注释掉的做法,因为每次开始都要调用一次pow函数,
//会增加程序耗费时间,虽然对现在的机器似乎没关系.
//for(i=pow(10,n-1)+1;i<pow(10,n);i++)
i=pow(10,n-1)+1;
stop=pow(10,n);
for(;i<stop;i++)
{
m=0;//这里要恢复为0,否则就是累计了
for(j=1;j<=n;j++)
{
c=pow(10,j-1);
k=i/c;
a[j]=k%10;
m=m+b[a[j]];
}
if(i==m)
{
p=1;
printf("%d\n",i);//最好%d
}
}
if(p==0)
printf("No output\n");
}