方程组y=ax+2 y²=8x的两组解为(x1,y1)(x2,y2)(x1≠x2)若x1+x2=4方程组y=ax+2 y²=8x的两组解为(x1,y1)(x2,y2)(x1≠x2)若x1+x2=4,求(x1-x2)²+(y1-y2)²的值.
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![方程组y=ax+2 y²=8x的两组解为(x1,y1)(x2,y2)(x1≠x2)若x1+x2=4方程组y=ax+2 y²=8x的两组解为(x1,y1)(x2,y2)(x1≠x2)若x1+x2=4,求(x1-x2)²+(y1-y2)²的值.](/uploads/image/z/11640124-28-4.jpg?t=%E6%96%B9%E7%A8%8B%E7%BB%84y%3Dax%2B2+y%26%23178%3B%3D8x%E7%9A%84%E4%B8%A4%E7%BB%84%E8%A7%A3%E4%B8%BA%28x1%2Cy1%29%28x2%2Cy2%29%28x1%E2%89%A0x2%29%E8%8B%A5x1%2Bx2%3D4%E6%96%B9%E7%A8%8B%E7%BB%84y%3Dax%2B2+y%26%23178%3B%3D8x%E7%9A%84%E4%B8%A4%E7%BB%84%E8%A7%A3%E4%B8%BA%28x1%2Cy1%29%28x2%2Cy2%29%28x1%E2%89%A0x2%29%E8%8B%A5x1%2Bx2%3D4%2C%E6%B1%82%28x1-x2%29%26%23178%3B%2B%EF%BC%88y1-y2%29%26%23178%3B%E7%9A%84%E5%80%BC.)
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方程组y=ax+2 y²=8x的两组解为(x1,y1)(x2,y2)(x1≠x2)若x1+x2=4方程组y=ax+2 y²=8x的两组解为(x1,y1)(x2,y2)(x1≠x2)若x1+x2=4,求(x1-x2)²+(y1-y2)²的值.
方程组y=ax+2 y²=8x的两组解为(x1,y1)(x2,y2)(x1≠x2)若x1+x2=4
方程组y=ax+2 y²=8x的两组解为(x1,y1)(x2,y2)(x1≠x2)若x1+x2=4,求(x1-x2)²+(y1-y2)²的值.
方程组y=ax+2 y²=8x的两组解为(x1,y1)(x2,y2)(x1≠x2)若x1+x2=4方程组y=ax+2 y²=8x的两组解为(x1,y1)(x2,y2)(x1≠x2)若x1+x2=4,求(x1-x2)²+(y1-y2)²的值.